动态数组，可以存储不同数据类型
>>> a = ['spam', 'eggs', 100, 1234]>>> a['spam', 'eggs', 100, 1234]
和string一样，支持索引，+，*
>>> a[0]'spam'>>> a[3]1234>>> a[-2]100>>> a[1:-1]['eggs', 100]>>> a[:2] + ['bacon', 2*2]['spam', 'eggs', 'bacon', 4]>>> 3*a[:3] + ['Boo!']['spam', 'eggs', 100, 'spam', 'eggs', 100, 'spam', 'eggs', 100, 'Boo!']
和string不同，list的元素是可变的
>>> a['spam', 'eggs', 100, 1234]>>> a[2] = a[2] + 23>>> a['spam', 'eggs', 123, 1234]
可以给范围索引负值，另类的插入、删除操作
>>> # Replace some items:... a[0:2] = [1, 12]>>> a[1, 12, 123, 1234]>>> # Remove some:... a[0:2] = []>>> a[123, 1234]>>> # Insert some:... a[1:1] = ['bletch', 'xyzzy']>>> a[123, 'bletch', 'xyzzy', 1234]>>> # Insert (a copy of) itself at the beginning>>> a[:0] = a>>> a[123, 'bletch', 'xyzzy', 1234, 123, 'bletch', 'xyzzy', 1234]>>> # Clear the list: replace all items with an empty list>>> a[:] = []>>> a[]
len()内置函数用来测量长度
>>> a = ['a', 'b', 'c', 'd']>>> len(a)4
多维数组
>>> q = [2, 3]>>> p = [1, q, 4]>>> len(p)3>>> p[1][2, 3]>>> p[1][0]2
appen函数在数组末尾添加元素
>>> p[1].append('xtra')>>> p[1, [2, 3, 'xtra'], 4]>>> q[2, 3, 'xtra'] in操作符测试包含关系
def ask_ok(prompt, retries=4, complaint='Yes or no, please!'): while True: ok = input(prompt) if ok in ('y', 'ye', 'yes'): return True if ok in ('n', 'no', 'nop', 'nope'): return False retries = retries - 1 if retries < 0: raise IOError('refusenik user') print(complaint) 常用函数
- list. append ( x )
-
Add an item to the end of the list. Equivalent to a[len(a):] = [x].
- list. extend ( L )
-
Extend the list by appending all the items in the given list. Equivalent to a[len(a):] = L.
- list. insert ( i, x )
-
Insert an item at a given position. The first argument is the index of the element before which to insert, so a.insert(0, x) inserts at the front of the list, and a.insert(len(a), x) is equivalent to a.append(x).
- list. remove ( x )
-
Remove the first item from the list whose value is x. It is an error if there is no such item.
- list. pop ( [ i ] )
-
Remove the item at the given position in the list, and return it. If no index is specified, a.pop() removes and returns the last item in the list. (The square brackets around the i in the method signature denote that the parameter is optional, not that you should type square brackets at that position. You will see this notation frequently in the Python Library Reference.)
- list. index ( x )
-
Return the index in the list of the first item whose value is x. It is an error if there is no such item.
- list. count ( x )
-
Return the number of times x appears in the list.
- list. sort ( )
-
Sort the items of the list in place.
- list. reverse ( )
-
Reverse the elements of the list in place.
>>> a = [66.25, 333, 333, 1, 1234.5]>>> print(a.count(333), a.count(66.25), a.count('x'))2 1 0>>> a.insert(2, -1)>>> a.append(333)>>> a[66.25, 333, -1, 333, 1, 1234.5, 333]>>> a.index(333)1>>> a.remove(333)>>> a[66.25, -1, 333, 1, 1234.5, 333]>>> a.reverse()>>> a[333, 1234.5, 1, 333, -1, 66.25]>>> a.sort()>>> a[-1, 1, 66.25, 333, 333, 1234.5] list做栈用
>>> stack = [3, 4, 5]>>> stack.append(6)>>> stack.append(7)>>> stack[3, 4, 5, 6, 7]>>> stack.pop()7>>> stack[3, 4, 5, 6]>>> stack.pop()6>>> stack.pop()5>>> stack[3, 4]
list做队列用
>>> from collections import deque>>> queue = deque(["Eric", "John", "Michael"])>>> queue.append("Terry") # Terry arrives>>> queue.append("Graham") # Graham arrives>>> queue.popleft() # The first to arrive now leaves'Eric'>>> queue.popleft() # The second to arrive now leaves'John'>>> queue # Remaining queue in order of arrivaldeque(['Michael', 'Terry', 'Graham']) List Comprehensions 可读性更高，更简洁的集合初始化
>>> squares = []>>> for x in range(10):... squares.append(x**2)...>>> squares[0, 1, 4, 9, 16, 25, 36, 49, 64, 81]#等价于squares = [x**2 for x in range(10)]
>>> combs = []>>> for x in [1,2,3]:... for y in [3,1,4]:... if x != y:... combs.append((x, y))...>>> combs[(1, 3), (1, 4), (2, 3), (2, 1), (2, 4), (3, 1), (3, 4)]#等价于>>> [(x, y) for x in [1,2,3] for y in [3,1,4] if x != y][(1, 3), (1, 4), (2, 3), (2, 1), (2, 4), (3, 1), (3, 4)]
>>> vec = [-4, -2, 0, 2, 4]>>> # create a new list with the values doubled>>> [x*2 for x in vec][-8, -4, 0, 4, 8]>>> # filter the list to exclude negative numbers>>> [x for x in vec if x >= 0][0, 2, 4]>>> # apply a function to all the elements>>> [abs(x) for x in vec][4, 2, 0, 2, 4]>>> # call a method on each element>>> freshfruit = [' banana', ' loganberry ', 'passion fruit ']>>> [weapon.strip() for weapon in freshfruit]['banana', 'loganberry', 'passion fruit']>>> # create a list of 2-tuples like (number, square)>>> [(x, x**2) for x in range(6)][(0, 0), (1, 1), (2, 4), (3, 9), (4, 16), (5, 25)]>>> # the tuple must be parenthesized, otherwise an error is raised>>> [x, x**2 for x in range(6)] File "", line 1, in ? [x, x**2 for x in range(6)] ^SyntaxError: invalid syntax>>> # flatten a list using a listcomp with two 'for'>>> vec = [[1,2,3], [4,5,6], [7,8,9]]>>> [num for elem in vec for num in elem][1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> from math import pi>>> [str(round(pi, i)) for i in range(1, 6)]['3.1', '3.14', '3.142', '3.1416', '3.14159']
del 按索引删除
>>> a = [-1, 1, 66.25, 333, 333, 1234.5]>>> del a[0]>>> a[1, 66.25, 333, 333, 1234.5]>>> del a[2:4]>>> a[1, 66.25, 1234.5]>>> del a[:]>>> a[]
del 也可以用来删除变量
>>> del a